Help with Proof: Particle Falling Distance from vnot to v1

Thread starter qqchico
Start date Oct 3, 2005
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Proof

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The discussion centers on deriving the distance a particle falls in a constant gravitational field when it encounters a resisting force proportional to the square of its velocity. The formula for the distance fallen from an initial velocity (vnot) to a final velocity (v1) is provided. Participants express frustration with the proof process and question whether differential equations are necessary for the solution. The conversation highlights the complexity of the problem and the challenges of understanding the underlying physics. Ultimately, the need for clarity in solving such proofs is emphasized.

Oct 3, 2005

qqchico

the question asks consider a particle of mass m whose motion starts from rest in a constant gravitational field. if a resting force proportional to the square of the velocity (i.e, kmv^2) is encountered, show that the distance s the particle falls from vnot to v1 is given by

s(vnot-> v1)= 1/2 [(g-kvnot^2)/(g-kv12}]

I hate proofs

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Oct 4, 2005

James R

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Are you supposed to use differential equations to solve this?

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