Help with Simple Problem: Match Objects to Size Scales

  • Thread starter Thread starter Alkatran
  • Start date Start date
  • Tags Tags
    Match
AI Thread Summary
The discussion revolves around matching various objects to their corresponding size scales. The user initially attempted the combination CFDBBA but found it incorrect. They confirmed that the diameter of a hair is E, while the sizes of a window pane, proton, and oil molecule were deemed correct. Suggestions were made to try combinations like CFDEBA and CCDEBA, with some uncertainty about the size of a twig, which could fit either centimeter or millimeter scales. Ultimately, the user ran out of attempts without finding the correct match.
Alkatran
Science Advisor
Homework Helper
Messages
959
Reaction score
0
I need help with a very simple problem. Here it is:

8. [2pt] Match the object with the size scale.
(E.g., if the first corresponds to B, and the others to C, enter BCCCCC)
1) Thickness of a window pane.
2) Diameter of a twig.
3) Diameter of a proton.
4) Diameter of a hair.
5) Size of an oil molecule
6) Size of a robin.

A. 1e-1 m (decimeter)
B. 1e-9 m
C. 1e-2 m (centimeter)
D. 1e-15 m
E. 1e-4 m (tenth of a millimeter)
F. 1e-3 m (millimeter)

Note that you can put in N, meaning "none of the above"


Now, what I have so far is:
CFDBBA (incorrect)

I have 20 tries on an automated system for this, but I wasted 10 when I thought you could only put a letter once, and 9 more thinking there were no Ns. Any help?
 
Physics news on Phys.org
4 is definitely E (not B) : hair is usually 50 to 100 microns in diameter.

I'd try CFDEBA and if that fails, CCDEBA (you can have thick twigs)
 
Windowpane, proton and molecule are correct.

a twig could be either cm or mm, I think that one is unfair, but you get to try both.
 
Chi Meson said:
Windowpane, proton and molecule are correct.

a twig could be either cm or mm, I think that one is unfair, but you get to try both.

I have one try left.
Make that 0 tries left.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top