Help with understand double integral solution?

Chandasouk
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I follow it up to the third step, but how did they get the bottom denominators of -4? shouldn't it be -1?
 
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∫(ax+b)ndx = (1/a(n+1))(ax+b)n+1+C

In their case, n=-2 and a=4
 
Oh, should I know that formula or do most people look that up in a table? Been a while since I did Calc 2.
 
Chandasouk said:
Oh, should I know that formula or do most people look that up in a table? Been a while since I did Calc 2.
You don't need to know that formula, but you should know how to derive it. rockfreak.667 used a very simple substitution to get it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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