How Do You Calculate Velocity from a Position-Time Equation?

  • Thread starter Thread starter chound
  • Start date Start date
  • Tags Tags
    Velocity
AI Thread Summary
To calculate velocity from the position-time equation x = a + b(t^2), where a = 8.5m and b = 2.5m/(s^2), one must differentiate the equation with respect to time. The derivative dx/dt yields the velocity function v(t). After differentiating, substituting t = 2s into the velocity function provides the specific velocity at that time. The discussion also briefly touches on differentiation concepts, indicating a broader interest in calculus applications. Understanding these principles is essential for solving similar physics problems effectively.
chound
Messages
163
Reaction score
0
The position of an object moving along x-axis is given by x=a+b(t*t) where a =8.5m, b=2.5m/(s*s) and t is time. What is the velocity at t=2s? I think differential calculus should be used :confused:
 
Physics news on Phys.org
If that x equation is x = a+bt^2, then just differentiate wrt to time to get velocity.
 
Yupp, just get dx/dt and then make t = 2.
 
Is it this:
dx/dt = d(a+bt^2)/dt
After this what should I do?
 
Do you know how to differentiate?

If y = a + bx^2, what is dy/dx?

You have x = a + bt^2, and you know v=dx/dt, so what is v(t)?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top