HELPSubstitution and Integral by Parts

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Homework Help Overview

The discussion revolves around evaluating an integral involving a Rayleigh distribution, specifically the integral of ((x^2)/a)*e^[-(x^2)/(2a)] from 0 to infinity. Participants are exploring methods to approach this integral and related calculations, such as finding E(x).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using integration by parts and substitution to tackle the integral. There are questions about how to handle the integral after applying these methods, particularly regarding the impact of the parameter 'a' and how it affects the calculations. Some participants express confusion over the antiderivative of the exponential function involved.

Discussion Status

There is an ongoing exploration of different methods to solve the integral, with some participants indicating progress on related questions while others express uncertainty about the original integral. Multiple interpretations and approaches are being considered, but no consensus has been reached on a definitive solution.

Contextual Notes

Participants note that the integral is part of a requirement to calculate E(x) for a Rayleigh distribution, and there are constraints related to the nature of the integral, specifically that it does not have a straightforward antiderivative.

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I'm having big trouble when trying to figure this integral out. Please help!

Integral (from 0 to infinity): ((x^2)/a)*e^[(-x^2)/2a] dx a is a constantThanks in advance!
 
Last edited:
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I would start with u = x and dv = (1/a)x*e-x2/(2a)dx.
 
OHHHH! Thank you sooo much! I'v been thinking my head off by trying to do substitution!

And I have one more question, I'm required to calculate E(x2) too, so now instead of (X^2)/a for the first part, it becomes (x^3)/a, and the 2nd part remains the same. How do I approach this one?

Thank you very much!
 
Oh wait a minute, after doing the parts, since V = - (e-x2/(2a)), now applying the fomula, uv - integral v du, how do I solve Integral - (e-x2/(2a)) dx ?
 
Hi Mark44, I think your method works perfectly w/ my 2nd question. I worked it out already. But I still don't know how to solve the 1st question.
 
Then I think you're stuck, unless there is some additional information we haven't seen yet. e-x2 doesn't have a nice neat antiderivative.
 
The question says Let X1...Xn be a random sample from a Rayleigh distribution with pdf
f(x) = (x/a)*e-x2/(2a), for x>0. That's it! And I'm suppose to find E(x).
 
thank you so much!
 
  • #10
Hi Dick, I read through the article on wiki, and I'm wondering how the parameter a in my problem affect the integral. I cannot ignore a here since the reason I'm calculating E(x) is becoz I'm trying to find the Method of Moment estimator of a.

Thank you!
 
  • #11
Set u^2=x^2/(2a). So u=x/sqrt(2a). If you write the integral in terms of u, you should be able to collect all of the a's outside of the integral.
 
  • #12
But it still doesn't solve the integral. it became: Integral 2u^2*e^(-u2)sqrt(2a)du
 
  • #13
Isn't it 2*sqrt(2a)*integral u^2*e^(-u^2)*du? The u integral is just a constant. I thought you were going to use integration by parts like Mark44 suggested to reduce it to the Gaussian integral?
 
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  • #14
Thank you very much!
 

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