HELPSubstitution and Integral by Parts

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I'm having big trouble when trying to figure this integral out. Please help!

Integral (from 0 to infinity): ((x^2)/a)*e^[(-x^2)/2a] dx a is a constantThanks in advance!
 
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OHHHH! Thank you sooo much! I'v been thinking my head off by trying to do substitution!

And I have one more question, I'm required to calculate E(x2) too, so now instead of (X^2)/a for the first part, it becomes (x^3)/a, and the 2nd part remains the same. How do I approach this one?

Thank you very much!
 
Oh wait a minute, after doing the parts, since V = - (e-x2/(2a)), now applying the fomula, uv - integral v du, how do I solve Integral - (e-x2/(2a)) dx ?
 
Hi Mark44, I think your method works perfectly w/ my 2nd question. I worked it out already. But I still don't know how to solve the 1st question.
 
Then I think you're stuck, unless there is some additional information we haven't seen yet. e-x2 doesn't have a nice neat antiderivative.
 
The question says Let X1...Xn be a random sample from a Rayleigh distribution with pdf
f(x) = (x/a)*e-x2/(2a), for x>0. That's it! And I'm suppose to find E(x).
 
thank you so much!
 
Hi Dick, I read through the article on wiki, and I'm wondering how the parameter a in my problem affect the integral. I cannot ignore a here since the reason I'm calculating E(x) is becoz I'm trying to find the Method of Moment estimator of a.

Thank you!
 
Set u^2=x^2/(2a). So u=x/sqrt(2a). If you write the integral in terms of u, you should be able to collect all of the a's outside of the integral.
 
But it still doesn't solve the integral. it became: Integral 2u^2*e^(-u2)sqrt(2a)du
 
Isn't it 2*sqrt(2a)*integral u^2*e^(-u^2)*du? The u integral is just a constant. I thought you were going to use integration by parts like Mark44 suggested to reduce it to the Gaussian integral?
 
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