Here's a theorem about the tangent function

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The discussion presents a theorem about the tangent function, stating that tan(x) = c if x equals tan^-1*c or tan^-1*c plus n(180) for any integer n. A specific problem is posed to find a solution to tan(x) = 1 between 270 and 450 degrees. The approach suggested involves first determining the general solution for c, which is 1 in this case, and then adjusting the angle by adding 180 degrees if necessary to fit within the specified range. It is noted that tan(x) = 1 corresponds to sin(x) = cos(x), making it easier to identify the angle. The discussion emphasizes the importance of understanding the periodic nature of the tangent function in solving the problem.
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1. Here's a theorem about the tangent function. tan(x) = c iff 1: x = tan^-1*c or 2: x = tan^-1*c+n(180) for some integer n. Find a solution to tan x = 1 between 270 and 450 degrees.




2.


3. I am not really sure how to go about starting this problem. I have only two problems in my homework, but no solution to either to self check.
 
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The way I would go about solving this is to first find an expression for all values of x that satisfy the equation, and then locate the specific x that falls in that range. They give you the general solution for c in the first sentence. In your case, c = 1.
 


In other words, find one angle such that tan x= 1 and if it is not between 270 and 450 degrees add 180 degrees until it is. I suppose you could use a calculator but since tan(x)= sin(x)/cos(x), tan(x)= 1 is the same as sin(x)= cos(x). It should be easy to find one angle x such that sin(x)= cos(x).
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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