Finding the Second Derivative of a Cubic Function

[gr3g1]

Hey guys,

My function is : y=(1-x^2)^3
I found my first derivative as : -6x(1-x^2)^2
But i can't seem to find the second derivative.

Do I use the product rule?

 

[gdumont]

You are right use the product rule
<br /> f(x)=u(x)v(x)<br />
then
<br /> f&#039;(x) = u&#039;(x)v(x) + v&#039;(x)u(x)<br />
here u(x)=-6x and v(x)=(1-x^2)^2

 

[gr3g1]

Thanks A lot