- #1
Mattman182
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Homework Statement
I have been given this problem but I don't think I'm doing it right as I have just disregarded n0?
Calculate the maximum length of material (nonlinear refractive index n2=2.5×10-19 cm2W-1) that can be traversed if the total accumulated phase difference between the beam centre (Intensity I =1×1011Wcm-2 , wavelength λ=1053nm) and the beam edge (I=0) is to be less than 2 rad.
Homework Equations
n = n0 + n2I
2πnL/λ = nkL
Φ(x) = n k L(x)
The Attempt at a Solution
I just combined the equations to get Φ = 2π/λ * (n0 + n2I)L
and put the numbers in but let n0 equal 1
So my answer was L = 3.35x10-7cm
I don't even know if I've used the right equations so help would be much appreciated