- #1

Mattman182

- 3

- 0

## Homework Statement

I have been given this problem but I don't think I'm doing it right as I have just disregarded n

_{0}?

Calculate the maximum length of material (nonlinear refractive index n

_{2}=2.5×10

^{-19}cm

^{2}W

^{-1}) that can be traversed if the total accumulated phase difference between the beam centre (Intensity I =1×10

^{11}Wcm

^{-2}, wavelength λ=1053nm) and the beam edge (I=0) is to be less than 2 rad.

## Homework Equations

n = n

_{0}+ n

_{2}I

2πnL/λ = nkL

Φ(x) = n k L(x)

## The Attempt at a Solution

I just combined the equations to get Φ = 2π/λ * (n

_{0}+ n

_{2}I)L

and put the numbers in but let n

_{0}equal 1

So my answer was L = 3.35x10

_{-7}cm

I don't even know if I've used the right equations so help would be much appreciated