(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A hockey player is standing on his skates on a frozen pond when an opposing

player skates by with the puck, moving with a constant speed of 12 m/s. After

3.0 s, the first player makes up his mind to chase his opponent and starts

accelerating uniformly at 3.8 m/s2. (a) How long does it take him to catch his

opponent? (b) How far does he travel before he catches up with his opponent?

3. The attempt at a solution

The position of player #2 is given by

x2 = x2i + v2i t + (1/2) a2 t2

x2 = (12 m/s) t

Equation: x1 = x1i + v1i (t - 3 s) + (1/2) a1 (t - 3 s)2

x1 = 0 + 0 + (1/2) (3.8 m/s2) (t - 3 s)2 = (1.9 m/s2) (t2 - 6 s t + 9 s2)

x1= x2

1.9t^{2}- 11.4t+17.1=12t

1.9t^{2}-23.4t+17.1=0

Now we plug these numbers into the quadratic equation and we get:

11.53 seconds

So the answer for PART A is 11.53 seconds.

b)

x2 = x2i + v2i t + (1/2) a2 t2

x2 = (12 m/s) t

x2 = (12 m/s) (11.53 s)

x2 = 138.36 m

The answer for PART b is138.36m

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# Homework Help: Hockey physics question

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