Hockey puck momentum, conservation of linear momentum

AI Thread Summary
The discussion focuses on a collision between two hockey pucks on an air-hockey table, where puck A (0.0480 kg) moves at +7.76 m/s and collides with stationary puck B (0.0960 kg). The conservation of momentum is applied in both the x and y directions to find the velocities of both pucks after the collision. The calculations suggest that the speed of puck B is approximately 3.595 m/s, while puck A's speed is around 4.77 m/s. The discussion seeks validation of these calculated speeds. The analysis effectively demonstrates the application of momentum conservation principles in a two-dimensional collision scenario.
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The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0480 kg and is moving along the x-axis with a velocity of +7.76 m/s. It makes a collision with puck B, which has a mass of 0.0960 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

There are no answers provided. Could someone please tell me if my answers are correct?

Momentum in the y direction
Piy = Pfy
0 = MaVasin65 + -MbVbsin37
MaVasin65 = MbVbsin37
Va = MbVbsin37 / Ma*sin65
Va = (0.096sin37Vb) / (0.048sin65)

Pix = Pfx
0.048(7.76) = 0.048cos65Va + 0.096cos37Vb

Plug Va in and you get Vb = 3.595 m/s and thus Va = 4.77 m/s ?
 
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