Calculating Delta-V in Hohmann Transfer Equation

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Calculating delta-v for a Hohmann transfer using the provided equation led to an unexpectedly small result of 0.00122149 m/s. The issue stemmed from an incorrect value for the gravitational parameter (μ), which should be calculated as GM, where G is the gravitational constant and M is the Earth's mass. The correct value for μ is approximately 4.651 x 10^14 m^3/s^2. Adjusting this value will yield a more accurate delta-v for the transfer. Proper calculations are essential for accurate orbital mechanics results.
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I'm having some slight difficulties in calculating the delta-v in a hohmann transfer equation. I used the equation from wikipedia (which i hope is correct) but whenever i replace the variables i get an extremely small delta-v, is this normal?

\Deltav=\sqrt{}(\mu/r1)*(\sqrt{}(2*r2/(r1+r2)-1))

r1=6374000 meters
r2=405500000 meters
\mu=9.814

my final result was 0.00122149m/s
it seems like a really small number, is this right or I'm i doing something really wrong?

i attached an excel sheet to show you my work.

thanks in advance
 

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Solistics said:
I'm having some slight difficulties in calculating the delta-v in a hohmann transfer equation. I used the equation from wikipedia (which i hope is correct) but whenever i replace the variables i get an extremely small delta-v, is this normal?

\Deltav=\sqrt{}(\mu/r1)*(\sqrt{}(2*r2/(r1+r2)-1))

r1=6374000 meters
r2=405500000 meters
\mu=9.814

my final result was 0.00122149m/s
it seems like a really small number, is this right or I'm i doing something really wrong?

i attached an excel sheet to show you my work.

thanks in advance

The problem is your value for \mu

\mu = GM

Where G is the universal gravitational constant and is equal to

6.67300 × 10-11 m3 kg-1 s-2

and M in this case is the mass of the Earth, or 5.97 x 1024 kg

so

4.651 X 10^{14}m^3 s^{-2}
 
thanks for that correction.
 
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