Hooke's law with a bungee jump

AI Thread Summary
To model a bungee jump using Hooke's law, a force balance on the jumper is necessary. The jumper's mass is 90kg, and the unstretched rope length is 15m, with the ability to adjust the length by +/- 0.5m. The rope extends by 1% for every 12N of tension, and the drag force is calculated as 0.3v^2. To determine how far the rope stretches in 0.02 seconds, one must incorporate the forces acting on the jumper, including gravity and drag, into the calculations. Understanding these dynamics is crucial for accurately modeling the bungee jump.
mickg77
Messages
3
Reaction score
0
Hi my problem is that I have to model a bungee jump and enter it into a flowchart. I've worked out the free-fall part, but my problem is that the jumper has now reached the point where hookes law comes into play.

The jumper mass is 90kg
The unstretched length of the rope is 15m(of neglible mass) but the bungee operator can change this at a rate of +/- 0.5ms at any time
It extends by 1% for every 12N if tension force. The drag force is 0.3v^2.

What I really want to do is calculate how far the rope has stretched in 0.02s. Is there any way of using time with Hooke's law?

Any help would be greatly appreciated.

Michael
 
Physics news on Phys.org
mickg77 said:
Hi my problem is that I have to model a bungee jump and enter it into a flowchart. I've worked out the free-fall part, but my problem is that the jumper has now reached the point where hookes law comes into play.

The jumper mass is 90kg
The unstretched length of the rope is 15m(of neglible mass) but the bungee operator can change this at a rate of +/- 0.5ms at any time
It extends by 1% for every 12N if tension force. The drag force is 0.3v^2.

What I really want to do is calculate how far the rope has stretched in 0.02s. Is there any way of using time with Hooke's law?

Any help would be greatly appreciated.

Michael

You have to carry out a force balance on the jumper.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...

Similar threads

Replies
12
Views
3K
Replies
3
Views
4K
Replies
5
Views
3K
Replies
26
Views
5K
Replies
9
Views
3K
Replies
12
Views
2K
Replies
7
Views
5K
Back
Top