Solving for y: A Step-by-Step Guide

[franky2727]

ive got (y-1/y+2)=Ke^3/4x4where K=+ or- e^3c

and I am trying to get to y=(2Ke^3/4x4)/(1-Ke^3/4x4)

but i keep getting y= (-3+Ke^3/4x4)/(Ke^3/4x4) can someone please have a go at this to see if its me that's wrong or the answer sheet and if its me which it usualy is can you please write your working step by step? thanks

 

[3029298]

We have:

$$\frac{y-1}{y+2}=KL$$

In which $$K=\pm e^{3c}$$ and $$L=e^{\frac{3}{4}x^4}$$

We now work this out:

$$y-1=yKL+2KL$$

$$y=yKL+2KL+1$$

$$y-yKL=2KL+1$$

$$y(1-KL)=2KL+1$$

$$y=\frac{2KL+1}{1-KL}$$

This does not correspond to the solution you want to get, but in my opinion this is the correct one, maybe you have not given the correct question?

 

[franky2727]

ye that's right sorry i forgot to put the +1 on the end and that way is about 50^2 times simpler than the way i was trying to do it thanks!

 

[3029298]

no problem sometimes the math becomes easier if you just replace some nasty crap by a single parameter