Horizontal velocity for projectile motion

AI Thread Summary
In projectile motion, the horizontal velocity of a bullet fired from a moving plane is influenced by both the plane's speed and the bullet's velocity. The bullet's horizontal velocity is calculated using the formula Vx = Vo * Cos(37°), resulting in 319.45 m/s. When considering the plane's horizontal speed of 200 m/s, the total horizontal velocity of the bullet becomes 519.45 m/s from a ground observer's perspective. This demonstrates the principle of relative motion, where the bullet's speed varies depending on the observer's frame of reference. Understanding this concept is crucial for solving problems related to projectile motion.
Michael Ngo
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Homework Statement


There was a plane with the height of 1 km above the ground. The plane is moving horizontally 200 m/s and can fire a bullet with the velocity of 400 m/s. At one time, the the gun form an angle of 37(degree) and fired the bullet.

I was confused with the horizontal (x-axis) velocity of the bullet. Does the velocity of the plane firing the gun also relevant or does it not ?

Homework Equations


The equation for the horizontal velocity of the bullet should be :
Vx = Vo. Cos37

The Attempt at a Solution


So it should be
Vx = Vo. Cos37 = 319.45 m/s

If the plane is moving 200 m/s horizontally. Does it add up with the horizontal velocity of the bullet? Like for say the total horizontal velocity of the bullet is 319.45 m/s + 200 m/s = 519.45 m/s .

Can someone explain it to me ? Sorry for asking such trivial question
 
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This is about relative motion, right? So it depends on your frame of reference. According to the plane's frame of reference, the bullet would be moving 319 m/s, but according to someone on the ground, the bullet would be moving at 519 m/s.
 
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Oh, i see. So its relative. Thank you sir
 
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