Hot metal added to Water, Heat Capacity Problem

AI Thread Summary
To find the final temperature of a copper-water mixture, the heat lost by the copper must equal the heat gained by the water. The specific heat of copper is 0.385 J/g K, and the equation q = (specific heat)(mass)(change in Temp.) applies to both substances. By setting the heat loss of copper equal to the heat gain of water, an equation can be formed with the final temperature as the unknown. It is important to remember that the final temperature will be the same for both the copper and the water. Solving this equation will yield the final temperature of the mixture.
Nick_273
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Homework Statement



A 100.0 g copper sample (specific heat 0.385 J/g K) at 100 C is added to 50.0 g of water at 26.5 C. What is the final temperature of the copper-water mixture?

Homework Equations



q = q(copper) + q(water)

q = (heat capacity)(change in Temp.)

q = (specific heat)(mass)(change in Temp.)


The Attempt at a Solution



So far i have found the heat capacity of copper to be 0.385 J/K

I know the metal loss of heat must equal the waters gain in heat but i do not know how to calculate the gain/loss.
 
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It seems you have the idea. To find the final temperature, try setting -qcopper = (specific heat)(mass)(change in Temp.) equal to qwater = (specific heat)(mass)(change in Temp.)

Another thing to keep in mind that should help you solve for final temperature, is that the at the end, the temperature of the water and the copper are going to be equal. So, if you think about what (change in Temp) really is, you should find yourself with an equation and one unknown, Tfinal, and from there you should be able to solve for temperature at the end.
 
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