How Are Distances from the Center of Mass Determined in Classical Mechanics?

AI Thread Summary
The discussion focuses on the determination of distances from the center of mass in classical mechanics. The equations r1' = -\frac{m_{2}}{m_{1}+m_{2}}r and r2' = \frac{m_{1}}{m_{1}+m_{2}}r represent the distances from the center of mass to two masses, m1 and m2, respectively. It is established that when the origin is set at the center of mass, the sum of the moments must equal zero, leading to the derived equations. The relationship between the masses and their distances is crucial for understanding the center of mass concept. This mathematical framework is essential for solving problems related to the motion of systems of particles.
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Homework Statement



I am reading a classical mechanics textbook and I don't understand how they found that.

r1' = -\frac{m_{2}}{m_{1}+m_{2}}r

and

r2' = \frac{m_{1}}{m_{1}+m_{2}}r

r1' is the vector from the center of mass R to m1 and r2' is the vector from the center of mass R to m2.




Homework Equations



Center of mass = \frac{m_{1}r_{1}+m_{2}r_{2}}{m_{1}+m_{2}}

The Attempt at a Solution

 

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If the origin is at the center of mass (which it is for ##r_1'## and ##r_2'##) then by definition of the center of mass
$$
\sum_i m_i r_i = 0
$$
The distance between masses 1 and 2 being ##r \equiv r_2' - r_1'##, we have
$$
\begin{align}
m_1 r_1' &= -m_2 r_2' \\
m_1 r_1' &= -m_2 (r + r_1') \\
r_1' (m_1 + m_2) &= - m_2 r \\
r_1' &= -\frac{m_2}{m_1 + m_2} r
\end{align}
$$
 
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