How Are Resultants Calculated for Parallel vs Perpendicular Distributed Loads?

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Discussion Overview

The discussion revolves around the calculation of resultants for parallel versus perpendicular distributed loads on beams. Participants explore the differences in how these loads are treated in terms of resultant forces.

Discussion Character

  • Exploratory, Technical explanation

Main Points Raised

  • One participant questions whether the resultant for parallel distributed loads is calculated in the same manner as for perpendicular distributed loads.
  • Another participant describes that an axial distributed load has a cumulative effect, suggesting that the resultant force at a specific point on the beam is the sum of all forces to the left, indicating a variation in force along the beam.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants have differing views on the calculation methods for resultants of parallel versus perpendicular loads.

Contextual Notes

Some assumptions about the nature of the distributed loads and their effects on the beam may not be fully articulated, leading to potential ambiguity in the discussion.

tigertan
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Hi there,


Parallel distributed loads are throwing me off a little at the moment. Is the resultant worked out the same way as for those with distributed loads perpendicular to a beam??


Picture included.

Thanks in advance
 

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lotsa views yet no help..

please post a reply??
 
An axial distributed load such as you've drawn would have a cumulative effect, so the force at the right end of the beam would be the sum of all forces to its left. In effect, you've drawn a force which increases with position from left to right.
 
Last edited:
Thx :)
 

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