How Can an AC Generator Be Converted to Produce DC?

  • Thread starter Thread starter jumpyroo92
  • Start date Start date
  • Tags Tags
    Ac/dc Generator
AI Thread Summary
To convert an AC generator to produce DC, a commutator can replace the slip rings, allowing for rectification of the alternating current. The output may not be steady DC, as the induced emf varies with the angle of the coil in the magnetic field. Participants in the discussion question the assumption of a sinusoidal output, suggesting that this could indicate fluctuations rather than a constant DC. The relationship between the coil's angle and the emf is crucial in determining the nature of the output. Overall, the conversion process and the characteristics of the resulting current require careful consideration of the generator's design and operation.
jumpyroo92
Messages
3
Reaction score
0

Homework Statement


How might you convert the generator in (http://www.aerospaceweb.org/question/propulsion/jet/generator.jpg) so that instead of producing alternating emf and current it will produce direct current? Would it be a steady D.C? Sketch a graph to show how the emf would vary with time.


Homework Equations





The Attempt at a Solution


(http://image.tutorvista.com/content/electricity/dc-generator.jpeg)
I drew something like this. In other words, I assumed that you just change the slop rings into a commutator.
I don't know about whether or not it'd be steady D.C.
As for the graph I think it's just a sinusoidal graph?
 
Physics news on Phys.org
jumpyroo92 said:

The Attempt at a Solution


(http://image.tutorvista.com/content/electricity/dc-generator.jpeg)
I drew something like this. In other words, I assumed that you just change the slop rings into a commutator.
I don't know about whether or not it'd be steady D.C.
As for the graph I think it's just a sinusoidal graph?

yes the commutator will work. But as the angle coil makes with field goes from 90° to 0°, does the emf remain constant?

Why do you think it is a sinusoidal graph? (this will directly show whether or not is a steady DC)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top