How Can Cylindrical Coordinates Simplify Complex Number Integration?

AI Thread Summary
Using cylindrical coordinates simplifies the integration of complex numbers by transforming the Cartesian coordinates (x, y) into polar coordinates (r, φ). The integral can be expressed as a double integral over r and φ, which is easier to evaluate. The transformation allows for the simplification of the term (x^2 + y^2)^n, making the integration process more manageable. The discussion highlights the effectiveness of this approach in resolving complex integrals. Ultimately, cylindrical coordinates provide a valuable method for simplifying complex number integration.
tanaygupta2000
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Homework Statement
Show that (1/π) ∫∫d(Re{a})d(Im{a}) |a><a| = I

where |a> is a coherent state = exp(-a*a/2) (a^n)/√n! |n>
and I is identity operator
Relevant Equations
|a> = exp(-a*a/2) Σ(a^n)/√n! |n>
<a| = exp(-a*a/2) Σ(a*^n)/√n! <n|
|n><n| = I
Capture.PNG


I began this solution by assuming a = x+iy since a is a complex number.
So I wrote expressions of <a| and |a> in which |n><n| = I.
I got the following integral:

Σ 1/πn! ∫∫ dx dy exp[-(x^2 + y^2)] (x^2 + y^2)^n I

I tried solving it using Integration by Parts but got stuck in the (x^2 + y^2)^n part.
Please help how can I evaluate this integral in an easier way.
Thank You !
 
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Why don't you regard x and y are coordinates of xy plane and achieve integration by cylindrical coordinates i.e.
\int dx \int dy = \int_0^{2\pi} d \phi \int_0^\infty r dr
 
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anuttarasammyak said:
Why don't you regard x and y are coordinates of xy plane and achieve integration by cylindrical coordinates i.e.
\int dx \int dy = \int_0^{2\pi} d \phi \int_0^\infty r dr
Yess! It very well worked! Lots of Thanks.
 
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