How Can Cylindrical Coordinates Simplify Complex Number Integration?

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Using cylindrical coordinates simplifies the integration of complex numbers by transforming the Cartesian coordinates (x, y) into polar coordinates (r, φ). The integral can be expressed as a double integral over r and φ, which is easier to evaluate. The transformation allows for the simplification of the term (x^2 + y^2)^n, making the integration process more manageable. The discussion highlights the effectiveness of this approach in resolving complex integrals. Ultimately, cylindrical coordinates provide a valuable method for simplifying complex number integration.
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Homework Statement
Show that (1/π) ∫∫d(Re{a})d(Im{a}) |a><a| = I

where |a> is a coherent state = exp(-a*a/2) (a^n)/√n! |n>
and I is identity operator
Relevant Equations
|a> = exp(-a*a/2) Σ(a^n)/√n! |n>
<a| = exp(-a*a/2) Σ(a*^n)/√n! <n|
|n><n| = I
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I began this solution by assuming a = x+iy since a is a complex number.
So I wrote expressions of <a| and |a> in which |n><n| = I.
I got the following integral:

Σ 1/πn! ∫∫ dx dy exp[-(x^2 + y^2)] (x^2 + y^2)^n I

I tried solving it using Integration by Parts but got stuck in the (x^2 + y^2)^n part.
Please help how can I evaluate this integral in an easier way.
Thank You !
 
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Why don't you regard x and y are coordinates of xy plane and achieve integration by cylindrical coordinates i.e.
\int dx \int dy = \int_0^{2\pi} d \phi \int_0^\infty r dr
 
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anuttarasammyak said:
Why don't you regard x and y are coordinates of xy plane and achieve integration by cylindrical coordinates i.e.
\int dx \int dy = \int_0^{2\pi} d \phi \int_0^\infty r dr
Yess! It very well worked! Lots of Thanks.
 
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