How can I accurately find the line currents in a Wye-Delta three phase circuit?

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Discussion Overview

The discussion revolves around finding the line currents in a Wye-Delta three-phase circuit, focusing on the application of mesh analysis and the conversion of load impedances between Delta and Wye configurations. Participants explore the implications of these conversions and the accuracy of their calculations.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about obtaining incorrect results when converting Delta load to Wye load using the formula Zwye = (1/3)Zdelta and questions the validity of their approach.
  • Another participant challenges the correctness of the mesh analysis results, noting that the line currents should have the same magnitude and be 120 degrees apart.
  • A third participant points out potential errors in labeling voltage supplies and suggests that the equations for mesh analysis may be incorrect, urging a review of current flow through impedances.
  • One participant requests recommendations for books with more examples of similar problems.
  • Another participant asserts that the method of dividing phase voltage by total line impedance is incorrect for a three-wire circuit and proposes alternative methods for calculating line currents.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the initial calculations or the mesh analysis. Multiple competing views on the methods for finding line currents remain, and the discussion is unresolved.

Contextual Notes

Participants express uncertainty regarding the accuracy of voltage labeling and the impact of specific impedances on current calculations. There are also unresolved questions about the application of mesh analysis in this context.

scothoward
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Hi,

In the attached file, the question asks to find the three line currents. I understand the solution using Mesh Analysis that was used. However, I am unsure as to why when I convert the Delta Load to a Wye load, I get the wrong answer.

Using Zwye = (1/3)Zdelta, adding the series line impedance with the load impedance, and then finding the line current using a single phase equivalent.


Essentially the Balanced Delta load becomes a Balance Wye load of 4 + j0.666. Then the line impedances will be in series with each individual load. So each impedance should be (4 + j0.666) + (1 + j2). Finally, the line currents will be the phase voltages (100 angle0, 100 angle-120, 100 angle120) divided by the series line and load impedance, 5 + j2.666.

Am I doing something wrong?

(I posted this in Homework Help 3 days ago, but received no response:frown:)
 

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Are you sure the answers from the mesh analysis are correct? The line currents, IaA, IbB, IcC, should all have the same magniture and be 120 apart. Your Zwye has problems also.
 
Looking at your figure you will notice you have at least one voltage supply labeled incorrectly. You show both B&C phases as 100volts at an angle of 120 degrees. Although it appears that you corrected for it in your mesh 2 equations, if mesh two is correct, then the same voltage in mesh one is shown incorrectly. I get a different set of equations for mesh one than you have. Take yor time and look at where the current for each loop flows. Ask yourself, is mesh one current the only current that flows through this impedance? Another item is I do not see the impedance (12+j12) as having any affect on your current loops. Do you think that is correct?

Hope this helps.
 
Can anybody please help me to find a book where I can find more examples of this kind of problem.
Thanks
 
oh u can't solve for the line current with the phase voltage divided by the total line impedance.
that's perfectly wrong. u can only do that if that is a four-wire circuit but since it's a three wire circuit, that's wrong...there are ways to solve that
1) calculate for the total impedance in delta connection, then convert the supply source into delta connection, dividing the voltage over the impedance gives u the total line current.
2) use mesh equations just like in the solution.
 

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