How can I calculate the moment of inertia for a rod bent into a square shape?

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SUMMARY

The moment of inertia for a uniform density rod bent into a square shape can be calculated using the mass M and length L of the rod, with the side length "a" defined as "L/4". The axis of rotation is at the center of the square. This discussion clarifies the relationship between the rod's dimensions and its moment of inertia, providing a foundational understanding for further calculations.

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with uniform density materials
  • Basic geometry of squares and rods
  • Knowledge of rotational axes in physics
NEXT STEPS
  • Calculate the moment of inertia for a square shape using the formula I = (1/12) * M * (a^2 + a^2) for rotation about the center
  • Explore the parallel axis theorem for additional scenarios
  • Research the moment of inertia for other geometric shapes, such as circles and triangles
  • Learn about the impact of varying density on moment of inertia calculations
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the principles of rotational dynamics and moment of inertia calculations.

S[e^x]=f(u)^n
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So i have a uniform density rod of mass M and length L. Now i want to bend it into a square shape with side length "a" where a is equal to "4/L". The thing is i only know how to calculate moment of inertia for objects with constant radii. does anybody have any recommendations to help me along?
 
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I think you mean a is equal to L/4. Where is the axis of rotation? The center of the square?
 
yes... in both cases lol
 

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