How can I define the integral of product spaces using characteristic functions?

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Homework Help Overview

The discussion revolves around defining the integral of product spaces using characteristic functions within the context of measure theory. The original poster is exploring how to express integrals of simple functions in a product measure space, specifically in relation to the integral of the product of two functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of characteristic functions to define integrals in product spaces. There is an exploration of expressing simple functions as sums of products of characteristic functions and the implications for integration.

Discussion Status

Some participants have suggested strategies for approaching the problem, including the use of simple functions and decomposing characteristic functions into products. There is an ongoing examination of the relationship between the integrals of the functions and the structure of the product space.

Contextual Notes

The discussion notes that Fubini's theorem cannot be applied due to the lack of sigma-finiteness in the measure spaces, which influences the approach to proving the integral equality. Participants are considering the implications of this constraint on their reasoning.

happysauce
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Homework Statement



I just have a question about the integral of a product space. How do I define the integral of product spaces in terms of characteristic functions?

What I mean by that is, if I have a measure space, (X,M,u) and f(x) is a positive, simple, measurable function. Then ∫f du = Ʃa_{i}u(E_{i}). What I want to know is how can I apply this to a simple function given the product space of (X,M,u) and (Y,N,v)?

The problem I have to do is to prove that ∫f(x)g(y)d(u×v)=(∫f(x)du)(∫g(y)dv), you can't use fubini's theorem since the problem doesn't assume the measure spaces are sigma finite and the hint suggested using standard limit theorems for integrals, which made me think I probably had to use simple functions...
 
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happysauce said:
How do I define the integral of product spaces in terms of characteristic functions?

The same as any other measure space.

What I mean by that is, if I have a measure space, (X,M,u) and f(x) is a positive, simple, measurable function. Then ∫f du = Ʃa_{i}(E_{i}). What I want to know is how can I apply this to a simple function given the product space of (X,M,u) and (Y,N,v)?

The same as any other measure space.

The problem I have to do is to prove that ∫f(x)g(y)d(u×v)=(∫f(x)du)(∫g(y)dv), you can't use fubini's theorem since the problem doesn't assume the measure spaces are sigma finite and the hint suggested using standard limit theorems for integrals, which made me think I probably had to use simple functions...

This sounds like a good strategy. But you probably want to restrict yourself to simple functions of the form f(x)=\sum a_i\chi_{E_i}(x) where the E_i are "rectangles" in the product space. Can you decompose the characteristic function of a rectangular region into a product of characteristic functions on the "component" spaces?
 
That's what I tried. I took the product of the integrals and expressed them as a product of two sums [\suma_{i}u(E_{i}) ][\sumb_{j}v(E_{j})], one summed n parts the other summed m parts. Then I noticed that the product created a sum of n×m rectangles and I was able to express it in terms of one sum.
 
happysauce said:
That's what I tried. I took the product of the integrals and expressed them as a product of two sums [\suma_{i}u(E_{i}) ][\sumb_{j}v(E_{j})], one summed n parts the other summed m parts. Then I noticed that the product created a sum of n×m rectangles and I was able to express it in terms of one sum.

OK, so you proved the theorem for the special case simple functions, where for every \chi_{E_j} holds that E_j is a rectangle. What did you do next?
 

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