How Can I Find Eigenvalues and Normalized Eigenvectors for a Matrix?

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SUMMARY

The discussion focuses on finding eigenvalues and normalized eigenvectors for the matrix defined by the rotation transformation: cosθ sinθ; -sinθ cosθ. The eigenvalues are determined to be λ = cosθ ± isinθ. The challenge arises in calculating the corresponding eigenvectors, where the user initially concludes that the only solution is the null vector, which is invalid. The resolution involves recognizing that x and y can be complex, allowing for solutions such as x = 1 and y = i.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically eigenvalues and eigenvectors.
  • Familiarity with complex numbers and their properties.
  • Knowledge of matrix operations and transformations.
  • Experience with mathematical notation and problem-solving techniques in eigenvalue problems.
NEXT STEPS
  • Study the properties of complex eigenvalues and their implications in linear transformations.
  • Learn how to compute eigenvectors for matrices with complex eigenvalues.
  • Explore the applications of eigenvalues and eigenvectors in various fields such as quantum mechanics and stability analysis.
  • Investigate numerical methods for finding eigenvalues and eigenvectors using software tools like MATLAB or Python's NumPy library.
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Students and professionals in mathematics, physics, and engineering who are working with linear algebra, particularly those dealing with complex matrices and eigenvalue problems.

debjit625
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Homework Statement


Find the eigen values and normalized eigen vectors for the matrix

cosθ sinθ
-sinθ cosθ

2. The attempt at a solution
Well I did the eigen values hope they are correct but can't solve for eigen vectors

Eigen values are
λ = cosθ ± isinθ

on solving for eigen vector for eigen value λ = cosθ + isinθ ,I got
x + iy = 0 ,hence only solution x = y = 0 which is not the solution I guess (eigen vector can't be null vector)
or could I take y = i and x = 1 then it is solvable but again can I take imaginary numbers ?

Thanks
 
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debjit625 said:
x + iy = 0 ,hence only solution x = y = 0

x and y are not necessarily real.
 
That means I take y = i and x = 1.
Thanks.
 

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