How can i make a graph of velocity vs time taking into account air resistance?

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To sketch a velocity vs. time graph for an object falling from rest while accounting for air resistance, the graph will initially be a curve that flattens out as the object approaches terminal velocity. At low speeds, air resistance is linear, but as speed increases, it becomes proportional to the square of the speed, eventually balancing the force of gravity. The graph will show a smooth curve that approaches a constant speed, indicating zero acceleration at terminal velocity. It's important to avoid sharp points or jumps in the graph, as acceleration never truly reaches zero. The resulting graph will be above the x-axis, indicating that velocity increases but at a decreasing rate over time.
nnis13
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How can i sketch a graph of velocity vs time for an object falling from rest taking into account air resistance.

Will it be a curve ?

How can i do it?
 
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nnis13 said:
How can i sketch a graph of velocity vs time for an object falling from rest taking into account air resistance.

Will it be a curve ?

How can i do it?
At low speeds the air resistance is a linear function of speed and at higher speeds it is proportional to the square of the speed. Eventually the resistance builds up so that it is equal to the body's weight. What happens to the speed then?

AM
 
Andrew Mason said:
At low speeds the air resistance is a linear function of speed and at higher speeds it is proportional to the square of the speed. Eventually the resistance builds up so that it is equal to the body's weight. What happens to the speed then?

AM

I am new to physics so i don't understand very much so can you please explain in a bit more detail or provide a link that shows a graph of this type please ?
 
nnis13 said:
I am new to physics so i don't understand very much so can you please explain in a bit more detail or provide a link that shows a graph of this type please ?
To being, draw the velocity time graph of a body falling due to gravity without resistance. That will be a line v = at where a = g to begin. As velocity increases, resistance increases so a gets smaller. So what happens to the graph? Does the graph get steeper or flatter? At some point, the resitance is equal to the force of gravity. What happens to the graph at that point?

AM
 
Andrew Mason said:
To being, draw the velocity time graph of a body falling due to gravity without resistance. That will be a line v = at where a = g to begin. As velocity increases, resistance increases so a gets smaller. So what happens to the graph? Does the graph get steeper or flatter? At some point, the resitance is equal to the force of gravity. What happens to the graph at that point?

AM

At a point where resitance is equal to the force of gravity i think that it will be 0 acceleration but constant speed but how can i draw this ??

Will it look like this > http://www.juniata.edu/faculty/roth/QM/Images/incConcUpLabel.gif

or like this http://www.juniata.edu/faculty/roth/QM/Images/decConcDownLabel.gif

By the way thanks a lot for answering
 
nnis13 said:
At a point where resitance is equal to the force of gravity i think that it will be 0 acceleration but constant speed but how can i draw this ??

Will it look like this > http://www.juniata.edu/faculty/roth/QM/Images/incConcUpLabel.gif

or like this http://www.juniata.edu/faculty/roth/QM/Images/decConcDownLabel.gif

By the way thanks a lot for answering
Let's say at t=15 seconds the acceleration is 0 and its speed,v, is 60 m/s. Plot that point on the graph. Now at t=16 seconds, what is v? At t=17, 18, 19, 20...? Connect those points. What does the graph look like?

AM
 
Andrew Mason said:
Let's say at t=15 seconds the acceleration is 0 and its speed,v, is 60 m/s. Plot that point on the graph. Now at t=16 seconds, what is v? At t=17, 18, 19, 20...? Connect those points. What does the graph look like?

AM
from 1-15 it will be a curve abd then from 16s until it hits the ground will be a straight line parallel to the x-axis ?

i am not sure about that but that's how i understood it
 
nnis13 said:
from 1-15 it will be a curve abd then from 16s until it hits the ground will be a straight line parallel to the x-axis ?

i am not sure about that but that's how i understood it

So is that right ?

That's what will look like ??
 
nnis13 said:
So is that right ?

That's what will look like ??

Yes, that's right. However, note that in theory, acceleration is never zero; the speed of an object approaches a certain speed (called terminal velocity) as the force of air resistance becomes closer and closer to the force of gravity, but never quite reaches it. So draw your graph as a smooth curve; don't include any jumps or pointy vertices.
 
  • #10
ideasrule said:
Yes, that's right. However, note that in theory, acceleration is never zero; the speed of an object approaches a certain speed (called terminal velocity) as the force of air resistance becomes closer and closer to the force of gravity, but never quite reaches it. So draw your graph as a smooth curve; don't include any jumps or pointy vertices.

Ok thanks for answering but i have one more question
Wil my curve be above the x-axis or below like this http://www.juniata.edu/faculty/roth/QM/Images/decConcDownLabel.gif
 
  • #11
I suppose you mean the t-axis, since this is a v vs. t graph. Think about it. Should velocity change faster as time passes, or should it change slower?
 
  • #12
ideasrule said:
I suppose you mean the t-axis, since this is a v vs. t graph. Think about it. Should velocity change faster as time passes, or should it change slower?

Yes the t-axis velocity changes slower i think
 
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