How can I prove the identity using Taylor's expansion?

kasse
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Homework Statement



Three slits of width a and d (separation of adjacent slits). d << the distance to the screen. Show that the intensity we observe is

I (\vartheta) = I_{1} \left[1 + 2 cos \left(\frac{2 \pi d sin\vartheta}{\lambda} ) \right] ^{2}



2. The attempt at a solution

For an angle \vartheta we see that the waves from slit 1 and 3 must travel a distance dsin\vartheta shorter and longer than the waves from slit 2 to get to a point on the screen.

Total wave amplitude far from the slits:

A = A1 + A2 + A3 = A _{0}sin(kx - \omega t - \varphi )+ A _{0}sin(kx - \omega t) + A _{0}sin(kx - \omega t + \varphi )

Am I on the right track? How do I find an easier expression for A?
 
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I think I should use complex notation here. How do I represent A in complex form? My book (and other sources on the internet that I've found) is not very clear here. My best guess is

A = A_{2}[exp(ikd sin\vartheta ) + 1 + exp(-ikd sin\vartheta )]

Can I then write exp(ikd sin\vartheta ) + exp(-ikd sin\vartheta ) = 2cos(kd sin \vartheta)? Why?
 
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1. You were actually right in your first attempt, except that you should square the amplitude and obtain the time average.

2. Yet, as in your second attempt, using complex notation is far easier.

3. exp(ix) = cos(x) + isin(x) can be used to prove the identity you want to use.
Above identity can be proved using taylor's expansion.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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