How can I solve for time in a pulley and ramp problem without a given variable?

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To solve the pulley and ramp problem, the forces acting on both masses must be analyzed using Newton's second law, F=ma. The tension in the cable was found to be T = -m1a + 98N, and substituting this into the equation for the second mass allowed for the calculation of acceleration. The main challenge is determining the time it takes for the masses to move 3 meters without knowing the ramp angle, θ. It is suggested that if the ramp angle is provided, kinematic equations can be used to find the time, which the textbook states is 1.13 seconds. Understanding the relationship between acceleration and displacement is crucial for solving the problem effectively.
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Homework Statement



A mass m{1} = 5kg is on a frictionless ramp and connected to a cable that passes over a pulley which is then attached to a second hanging mass, m{2} = 10kg. How long will it take the boxes to move 3m if they are released from rest?

F{A}= Forces acting on hanging object
F{B}= Forces acting on object on ramp

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Homework Equations



F=ma

The Attempt at a Solution



I have solved for T using the force equation on object A and got T= -m1a + 98N

Then I substituted for T in the equation for object B and solved for acceleration, yielding:a=(98N-49sin\vartheta)/15

My biggest problem is, the book says the answer is 1.13 seconds. How can I solve in terms of seconds without another variable provided? I can't think of a way to use elimination to solve for \vartheta.
 
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The image didn't come out.

But as to your question - assuming your are given the ramp angle - hint: kinematic equations.
 
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