How can I solve this integration problem using substitution?

[Dell]

how do i integrate this??

how do i integrate this function?

\intdx/(e^x-1)^0.5

i have tried all the methods i know and haven't cracked it, the best try i have had so far is

\intdx/(e^x-1)^0.5

===>t=e^x; dt=e^xdx

\intdt/t*(\sqrt{t-1})

now from here i tried integration in parts and got really complicated

u=1/\sqrt{t-1}
du=-dt/2(t-1)^1.5

dv=dt/t
v=ln(t)

=\intdt/t*\sqrt{t-1}=ln(t)/\sqrt{t-1}-\int-ln(t)dt/2(t-1)^1.5

how else can i solve this

 

[Tomboland]

http://integrals.wolfram.com/index.jsp?expr=(e^x-1)^-0.5&random=false

Integrals are hard

 

[daudaudaudau]

Use the substitution t=sqrt(exp(x)-1) => x=ln(t^2+1)