How can Kirchhoff's Laws be used to find node voltage in a circuit?

AI Thread Summary
Kirchhoff's Laws are essential for analyzing circuits, particularly for finding node voltages. Users are encouraged to apply Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL) to their circuit schematics for accurate results. Providing a schematic along with attempted calculations can help others offer targeted assistance. Common issues with voltage discrepancies may arise from incorrect application of these laws. Engaging with the community by sharing specific circuit details can lead to effective troubleshooting and solutions.
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Hi.. I'm trying to figure out how to find voltage over nodes in a circuit can anyone give me a crash course or just explain it... I've been using KCL to find it but my voltages are always out of whack... any suggestions would be helpful
 
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Show a schematic and your attempt to solve it, and we can help you.
 
Read about Kirkoff's Laws and apply them in your circuit. Otherwise, post a schematic and we may find an easier way to solve it.
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...
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