How can lithium be used for cold fusion through thermal neutron activation?

JuanCasado
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I would like to ask if any of you can comment on the thermal neutron activation of lithium in order to produce energy as a cold fusion-like process?
 
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The thermal neutron cross section isn't very big. http://www.nndc.bnl.gov/atlas/atlasvalues.html and the energy release isn't especially large. Q~7 MeV. Though, the Q value is sufficiently large that there's a good chance you'd breakup the resulting 7Li (QBU = -2.47 MeV), so that'll complicate things. Indeed, 6Li + n -> a + t is a way to breed more tritium in fusion reactors.

Then you have to get a thermal neutron source from somewhere, so you're basically running a nuclear reactor, so why don't you just use that as a power source?
 
There are more than one way to get neutrons:
http://en.wikipedia.org/wiki/Neutron_source
(Incidentally: Could some nuclear waste be used in order to do so?)
In case a nuclear reactor was the best choice, there is a reason of scale: A much smaller reactor is required to produce enough neutrons than to obtain the overall energy expected from the combined device...
 
Yes, I didn't mention other neutron sources as they wouldn't be what you'd end up using. You just can't get the flux from a AmBe source, as convenient as they are.
 
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I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
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