The thermal neutron cross section isn't very big. http://www.nndc.bnl.gov/atlas/atlasvalues.html and the energy release isn't especially large. Q~7 MeV. Though, the Q value is sufficiently large that there's a good chance you'd breakup the resulting 7Li (QBU = -2.47 MeV), so that'll complicate things. Indeed, 6Li + n -> a + t is a way to breed more tritium in fusion reactors.
Then you have to get a thermal neutron source from somewhere, so you're basically running a nuclear reactor, so why don't you just use that as a power source?
#4
JuanCasado
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There are more than one way to get neutrons: http://en.wikipedia.org/wiki/Neutron_source
(Incidentally: Could some nuclear waste be used in order to do so?)
In case a nuclear reactor was the best choice, there is a reason of scale: A much smaller reactor is required to produce enough neutrons than to obtain the overall energy expected from the combined device...
Yes, I didn't mention other neutron sources as they wouldn't be what you'd end up using. You just can't get the flux from a AmBe source, as convenient as they are.
Since E = mc^2, how can photons be massless? If a photon has no mass, then, according to Einstein's formula, its energy is given by E = 0 x c^2, which is 0. Yet, photons do have energy. This seems to be a complete contradiction. Please explain! Thank you.