PytrTchaikovsky said:
Is this
the thermal flux coefficient you mentioned?
No, that's the flux density [ W/m
2].
I would say that
k [ W/(K*m)] is closer. Actually the unit is [ (W*m)/(K*m
2 ) ], meaning that k*area/thickness [ W/K ] gives the "thermal flux coefficient". ( I think it's a term of my own? ). You can also call it "the specific thermal conductiviy" for a material.
PytrTchaikovsky said:
Are there any formulas out there?
No, but there are some "rule of thumb":
If you have a black copper plate, about 3mm thick and mounted vertically, the thermal
resistance will be θ = 600/A [ K/W ], where A is its area in cm
2. But I don't think your bottle is black, and it's not made of copper.
PytrTchaikovsky said:
How can I take this further to calculate the time it takes to heat the water?
You must make some differential equation, modelling your bottle containing water. The solution to the equation will be an exponential function. Isolate t (time) in an equation.
You may make a model by connecting a resistor and a capacitor in series and then charge the capacitor through the resistor. The current through the resistor is similar to the thermal flux, the voltage drop across the resistor is the temperature difference between air and bottle, the capacitor voltage is the temperature of the bottle.
The bottle is a difficult problem because when the air heats up the water, the warm water will be gathered at the top of the bottle and vica versa. So speaking of temperature of the water, you could ask: Where in the bottle?