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Homework Statement
A particle is in a infinite square poteltian well between x=0 and x=a. Find <p> of a particle whose wave function is \psi(x) = \sqrt{\frac{2}{a}}sin\frac{n \pi x}{a} (the ground state).
2. The attempt at a solution
<p> = \frac{2 \hbar k}{\pi} \int^{a}_{0}sin^{2} \frac{\pi x}{a} dx = \frac{2 \hbar k }{\pi} \int^{\pi}_{0}sin^{2}u du = \hbar k = p
which certainly isn't the answer I wanted. The correct answer is 0. Where's my mistake?