How can you express this w/o zero or negative exponents?

AI Thread Summary
The discussion focuses on simplifying the expression (9 - 9y^-2) / (y^-1 - y^0) raised to the power of 2 without using zero or negative exponents. Participants note that anything raised to the zero power equals one, which simplifies the expression. However, they acknowledge that negative exponents cannot be completely avoided but can be expressed as positive exponents in a fraction format. Multiplying both the numerator and denominator by y^2 is suggested to eliminate negative exponents while maintaining the expression's value. The importance of this multiplication is emphasized as it ensures the expression remains equivalent.
haengbon
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Homework Statement





9 - 9y-2
____________
y-1 - y0

this whole thing is then raised to 2 (I can't seem to format it that way:( )

Homework Equations



none

The Attempt at a Solution



I'm hoping someone would guide me through this :(
 
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Well, anything raised to the 0-th power is 1 so that simplifies that. I'm not entirely sure about your general question however. Are you looking for something that is simply expressed as positive exponents?
 
Pengwuino said:
Well, anything raised to the 0-th power is 1 so that simplifies that. I'm not entirely sure about your general question however. Are you looking for something that is simply expressed as positive exponents?

yes xD !
 
Well you can't get away from the fact that you'll have negative exponents. You can express the entire thing as a fraction of positive exponents however if that's what you're looking for; that is, you can get to \frac{something}{y^2}.
 
haengbon said:

Homework Statement





9 - 9y-2
____________
y-1 - y0

\left(\frac{9- 9y^{-2}}{y^{-1}- y^{0}}\right)^2
\left(9\frac{1- \frac{1}{y^2}}{\frac{1}{y}- 1}\right)^2

Multiply both numerator and denominator by y^2.

this whole thing is then raised to 2 (I can't seem to format it that way:( )

Homework Equations



none

The Attempt at a Solution



I'm hoping someone would guide me through this :(
 
HallsofIvy said:
\left(\frac{9- 9y^{-2}}{y^{-1}- y^{0}}\right)^2
\left(9\frac{1- \frac{1}{y^2}}{\frac{1}{y}- 1}\right)^2

Multiply both numerator and denominator by y^2.


I can't seem to understand why both the numerator and denominator needs to be multiplied by y2 :(
 
Because if you multiply only the numerator but not the denominator (or vice versa) by y2, you'll get something with a different value. If you multiply both numerator and denominator by the same value, you are multiplying by 1, which is the only number you can multiply by that doesn't change the value of the expression it multiplies.
 
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