David lopez said:
i am planning to measure the back emf produced by inductor when you open a switch. i know it is very hard to predict the voltage. but is there any
way to narrow the possibilities?
In principle, current of inductor cannot be changed instantaneously.
The inductor equation
V = L*dI/dt means that if the current changes suddenly, a very large voltage will be generated.
This means that after the switch is turned off, the inductor current will try hard to flow continuously at the same amplitude.
In short, let
Ia be the current just before turning off the switch, then the instantaneous voltage of the inductor just after turning off the switch is equal to
Ia multiplied by
Za (loading Impedance).
Namely
Va = Ia * Za, where
Va is instantaneous voltage of the inductor just after the switch is turned off.
Prediction Examples : -
Va will be very large if
Za is a very high resistance
Va will be extremely large if
Za is another high inductance inductor with zero initial current
Va will be nearly zero if
Za is a high capacitance capacitor with zero initial voltage
Va will be very difficult to be predicted if
Za is a complex network which containing L, C , R and other power sources.
...etc
Of course, the long-term varying of the inductor voltage/current after the switch is turned off is another story.
All in all, in today's times, using simulation to predict circuit behavior is much easier than analysis.