How Can You Solve the Equation 3^x + x = 4?

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To solve the equation 3^x + x = 4, isolating the exponential gives 3^x = 4 - x. Taking logarithms leads to the equation x log 3 = log(4 - x), but extracting x from the logarithm proves challenging. It is noted that an algebraic solution is not feasible. Observing the original equation suggests that an approximate value for x can be deduced intuitively. The discussion emphasizes the limitations of algebraic methods in solving this equation.
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Homework Statement

3^x + x = 4

solve for x.

Homework Equations



I'm thinking of using the logarithm laws. log(a.b) = log a + logb log(a/b) = log a - log b

log(a^b) = bloga

The Attempt at a Solution


Well if I isolate the exponential
3^x = 4-x

take logs on both sides

xlog3 = log(4-x)

I can't seem to get the x out of the log.
 
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You won't be able to find a solution algebraically. However the value for x is quite obvious. Take a good look at the equation in its original form.
 
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