How Close Must x Be to 2 for 5x+3 to Be Within 0.075 of 13?

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How close to 2 do we have to take x so that 5x+3 is within a distance of 0.075 from 13.
I am confuse on how to evaluate this problem.
 
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You should state your question more clearly.

A distance of 0.075 from 13 can be 13 + 0.075 or 13 - 0.075. Can you find an x such that 5x+3 evaluates to one of those two points?
 
5x+3 will be within distance 0.075 from 13 (above or below) as long as 5x+ 3 is between 13- 0.75 and 13+ 0.75 or 12.25\le 5x+ 3\le 13.75. Solve that inequality for x. How close is that to 2?
 
I understand that part but how do you work the problem out?
 
so x=1.85,2.15; then I would then subtract 2-1.85 and 2-2.15. my answer would be .15
 
Hey step: check out this web site. i thought it was helpful (the "flash" examples in particular)

http://archives.math.utk.edu/visual.calculus/1/definition.6/index.html
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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