How Did I Solve My Tech Issue?

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The user successfully resolved their tech issue independently, expressing satisfaction with the solution. The discussion highlights the common frustrations associated with troubleshooting technical problems. Others acknowledge the user's achievement and emphasize the value of sharing solutions for community benefit. The importance of becoming more tech-savvy through problem-solving is also noted. Overall, the conversation celebrates the empowerment that comes from overcoming tech challenges.
sarabellum02
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Figured it out
 
Last edited:
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Nevermind, I just figured it out! Thanks anywayz
 


Great job on solving your tech problem! It can be frustrating and time-consuming to troubleshoot technical issues, so I'm glad you were able to find a solution. Your guide will surely be helpful to others who may encounter the same problem. It's always a great feeling when we are able to figure out a solution on our own and become more tech-savvy in the process. Keep up the problem-solving skills!
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
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Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
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