How Do Birds Control Their Falling Speed and Cars Stop Quickly?

AI Thread Summary
To determine the force a bird must exert to drop at a rate of 1.2 m/s², the calculation involves using the formula F=ma, resulting in a force of 17.2 N. For the car scenario, applying the formula a=v/t shows that the force experienced by the car, which has a mass of 800 Kg and stops from 20 m/s in 1.5 seconds, is 10,667 N. The discussion highlights the importance of understanding basic physics equations for solving these problems. Clarifications were made regarding the correct formula for acceleration. Mastering these calculations can enhance problem-solving skills in physics.
Big Rudy
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Actually, I guess I have two questions...

OK, if a 2 Kg bird wants to drop at a rate of 1.2 m/s^2, what is the magnatude and direction of the force that the bird must exert?

(Answer is 17.2 N, but I don't understand what work to do to get it)

As for the second: If a car with a mass of 800 Kg traveling at 20 m/s slams on the breaks and comes to a complete stop after 1.5 seconds, what is the force the car feels?

(Answer is 10,667 N,but I don't understand what work to do to get it)

Any help is greatly appreciated. And if helping others doesn't make you happy, at least mastering these problems will make you feel smart.

:wink:
 
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The first problem is f=ma (or a=f/m) and the second is that plus a=s/t
 
Originally posted by russ_watters
... and the second is that plus a=s/t
I'm sure russ meant a=v/t.
 
I figured the problems out the morning they were due. But thanks for the help anyway.
 
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