How Do Contact Lenses Correct Myopia and Alter Near Point Vision?

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Contact lenses for correcting myopia should be concave lenses, which diverge light rays to extend the far point of vision. The focal length of these lenses can be calculated using the formula for myopia correction, which involves the patient's far point. When using corrective lenses, the near point of the patient will improve, allowing for clearer vision at closer distances. The specific near point after lens correction can be determined through calculations based on the lens power. Overall, concave lenses effectively enhance near point vision in myopic individuals.
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New user has been reminded to always show their work when posting schoolwork questions
Homework Statement
The patient is myopic.
Relevant Equations
1/f=1/p+1/q
Its near point is 13.0 cm from the eyes and its far point is 50.0 cm.
a) What type of contact lenses should be prescribed to correct his nearsightedness.
Determine their focal length
b) Determine the near point of the patient when using lenses for the correction of myopia.
 
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Show us what you have tried, please. Question a - what type of lens? -- for example
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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