How Do Currents in Adjacent Wires Affect Their Mutual Force?

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To determine the net force on a rectangular loop of wire near a straight wire with a current of 2.5A, the correct approach involves calculating the force on each segment of the loop due to the straight wire and summing these forces. The initial calculations used an incorrect distance and only considered one segment of the loop, leading to discrepancies with the textbook answer of 2.6 x 10^-6 N. Clarification on the dimensions of the loop and their application in the formula is necessary, as the distance from the straight wire to each segment must be accurately accounted for. Properly applying the formula with the correct distances and considering all segments will yield the correct net force. Further assistance is needed to resolve the calculation errors.
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Hi,

My Question:

A rectangular loop of wire lies in the same plane as a straight wire, as show in Fig. 20-57. There is a current of 2.5A in both wires. Determine the magnitude and direction of the net force on the loop.

http://www.webassign.net/pse/p31-09.gif"

where the width is 10.cm and width of the box is 5.0 cm and distance from the rectangular loop and the straight wire is 3.0 cm.

My Work

F=((mu constant)(I)^2(length))/(2pi(distance))
F=((4pi x 10^-7 Tm/A)(2.5A)^2(.10m))/(2pi(.05m))
F=2.5 x 10^-6 N

but the answer in the back of the book gives F=2.6 x 10^6

What did I do wrong:confused:

Thank You:smile:
 
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You need to calculate the force on each segment of the loop due to the long straight wire, and add them up. It looks to me like you only attempted to calculate the force on a single segment.

It also looks like you've plugged in the wrong distance (that's supposed to be the distance from the straight wire to the segment you are analyzing).

And this bit here is confusing:

where the width is 10.cm and width of the box is 5.0 cm and distance from the rectangular loop and the straight wire is 3.0 cm.

Which one is the "width"?
 
Sorry,

http://www.webassign.net/pse/p31-09.gif"

width=5 cm
Length= 10 cm
height= 3 cm

I thought the width would be used for the distance, but I guess that's wrong. I tried plugging in number but with no results close to the textbook answer of 2.6 x 10^-6 N

I still don't know what I did wrong though:confused:

Please help and Thank You
 
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