How Do Fermion Commutation Relations Affect Current Operators in 2D Spacetime?

In summary, the conversation discusses left-handed fermions in two spacetime dimensions and evaluates the commutator of a specific current operator using canonical equal-time anti-commutation relations. The result is then used to evaluate the limit of the commutator as the spacing between points approaches zero. The final result is a simple expression that may seem too easy but requires further investigation.
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Homework Statement


Consider left-handed fermions in two spacetime dimensions ##(t,x)##: ##\psi_L=\frac{1}{2}(1-\gamma_5)\psi_D## with ##J_0^\epsilon(t,x)=\psi_L^+(x+\epsilon)\psi_L(x-\epsilon)##.

(a). Use canonical equal-time anti-commutation relations for fermions to compute
##[J_0^\epsilon(t,x),J_0^\epsilon(t,y)]##

(b). Take ##\langle 0 \mid\psi_L^+(t,x)\psi_L(t,y)\mid 0 \rangle=\frac{1}{x-y}## and evaluate
##\langle 0 \mid[J_0^\epsilon(t,x),J_0^\epsilon(t,y)]\mid 0 \rangle## and its limit for ##\epsilon \rightarrow 0##.

Homework Equations

The Attempt at a Solution



For part (a) I got ##[J_0^\epsilon(t,x),J_0^\epsilon(t,y)]=\delta^3(x-y-2\epsilon)\psi_L^+(x+\epsilon)\psi_L(y-\epsilon)-\delta^3(y-x-2\epsilon)\psi_L^+(y+\epsilon)\psi_L(x-\epsilon)##.

Using this expression means for (b) I get in the limit ##\epsilon \rightarrow 0##

##\langle 0\mid [J_0^\epsilon(t,x),J_0^\epsilon(t,y)]\mid 0 \rangle=\frac{2\delta^3(x-y)}{x-y}##

which seems a bit too easy. What's going wrong?
 
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FAQ: How Do Fermion Commutation Relations Affect Current Operators in 2D Spacetime?

What are Fermion Commutation Relations?

Fermion commutation relations are a set of mathematical rules or relationships that describe how fermion particles, which are particles with half-integer spin, behave in a quantum system. These relations dictate how fermions interact with each other and with other particles.

Why are Fermion Commutation Relations important?

Fermion commutation relations are important because they help us understand the fundamental behavior of fermion particles in quantum systems. They also allow us to make predictions and calculations about the properties of these particles, which is essential in fields such as particle physics, quantum mechanics, and condensed matter physics.

What are the basic commutation relations for Fermions?

The basic commutation relations for Fermions are the anticommutation relations, which state that when two fermion operators are exchanged, the result is a negative sign. Mathematically, this can be written as {a, b} = ab + ba = 0, where a and b are fermion operators. This means that when a fermion is exchanged with another fermion, the resulting wavefunction changes sign.

What is the difference between Fermion and Boson commutation relations?

The main difference between Fermion and Boson commutation relations is that fermions follow the anticommutation rule, while bosons follow the commutation rule. This means that when two fermions are exchanged, the resulting wavefunction changes sign, whereas when two bosons are exchanged, the resulting wavefunction remains the same. This is due to the fundamental differences in the properties of fermions and bosons, such as their spin and statistics.

How do Fermion Commutation Relations relate to the Pauli Exclusion Principle?

Fermion commutation relations are closely related to the Pauli Exclusion Principle, which states that no two identical fermions can occupy the same quantum state simultaneously. This principle is a direct consequence of the anticommutation relations of fermion operators. It explains why fermions, such as electrons, can never occupy the same energy level in an atom, leading to the unique properties of matter.

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