How do I calculate maximum spring compression using the work-energy theorem?

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To calculate maximum spring compression using the work-energy theorem, the kinetic energy of a moving box is equated to the work done on the spring. The relevant equations include kinetic energy (1/2 mv^2) and Hooke's Law (F = ks). The maximum compression of the spring can be derived as s = [(m)(v)^2 / (k)]^1/2. It is emphasized that the energy stored in a spring is given by 1/2 kx^2, not kx^2. This approach effectively links the box's initial kinetic energy to the spring's potential energy at maximum compression.
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Homework Statement


A (m)kg box moving at (v)m/s on a horizontal, frictionless surface runs into a light spring of force constant (k)N/m.
Use the work-energy theorem to find the maximum compression of the spring.

Homework Equations


kinetic energy=1/2 m v^2
Change in kinetic energy = work done
hookes law: KS=F
FS=Work done

The Attempt at a Solution



(k)s^2= 0.5 x (m) x (v)^2

s =[0.5(m)(v)^2 / (k)] ^1/2

OR if
1/2 (k)s^2 = Work

0.5 (k) s^2 = 0.5 x (m) x (v)^2
s ^2 =0.5(m)(v)^2 / 0.5(k)
s=[(m)(v)^2 / (k)]^1/2
 
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cantgetno said:
OR if
1/2 (k)s^2 = Work

0.5 (k) s^2 = 0.5 x (m) x (v)^2
s ^2 =0.5(m)(v)^2 / 0.5(k)
s=[(m)(v)^2 / (k)]^1/2
That's the one you want. The energy stored in a spring is 1/2kx^2, not kx^2.
 
Thanks
 
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