How do I calculate the equilibrium temperature of a system?

AI Thread Summary
To calculate the equilibrium temperature of a system, it's essential to set the energy lost by the coffee equal to the energy gained by the ice and cream. The discussion highlights a common mistake of neglecting the specific heat capacity in the calculations. Participants emphasize the importance of expanding brackets and correctly isolating final temperatures in the equation. One user realized their error stemmed from assuming the specific heat capacities would cancel out, which led to an incorrect result. Properly accounting for all variables is crucial for arriving at the correct equilibrium temperature.
chukie
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I've found the question that I am doing at this site:
http://www.kent.k12.wa.us/pcpow/questions/phys/0105Bird/index.html

The answer is given here, but not the steps:
http://www.kent.k12.wa.us/pcpow/solutions/physics/0105bird/index.html


I know how to do Part A, but no matter how I tried to do part B (What was the thermal equilibrium temperature of that coffee), I do not get the answer given 56.97 degrees C.

I've followed the instructions in the solution and setted the energy lost by the coffee to be equal to the energy gained by the ice and the cream:

I've attached my work:
http://img139.imageshack.us/img139/231/worklb2.th.png

Can someone tell me what I did wrong?
 
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What you've done so far is fine. You need to expand the brackets and get all the final temps on one side and all the rest on the other. You've missed the specific heat capacity from some of the terms though.
 
Kurdt said:
What you've done so far is fine. You need to expand the brackets and get all the final temps on one side and all the rest on the other. You've missed the specific heat capacity from some of the terms though.

I did that but I got a value of -14194.9 =(
 
I'd check your working because using that method I get the answer. If possible write down all steps of your calculation so they can be checked.
 
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Like I said before you haven't included the specific heat capacity constant.
 
Kurdt said:
Like I said before you haven't included the specific heat capacity constant.

ahh i see! i assumed that the c's would cancel since they were all the same but i missed the fact that mL doesn't hv a c. thanks for your help!
 
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