How do I calculate the output current of an alternator

AI Thread Summary
Alternators do not strictly follow Ohm's law due to their inductive nature, which means their output current is influenced by rotor excitation rather than just resistance. Reducing rotor excitation decreases output voltage while maintaining constant load resistance, allowing for current calculations using Ohm's law. For example, an alternator with a voltage drop from 480V to 220V and a load resistance of 4 ohms results in a current drop from 120A to 55A. Understanding synchronous impedance, which accounts for inductive reactance and phase angles, is crucial for accurately predicting alternator behavior. In automotive applications, voltage regulators adjust excitation to maintain constant output voltage, further complicating the relationship with Ohm's law.
torbor
Do alternators obey Ohm’s law? The alternator output voltage is proportional to the rotor excitation current. When reducing rotor excitation, the output voltage drops and the load resistance stays constant. Can why still use ohm law to determine the output current.

Example alternator 480 v / 4 ohm current output is 120 a if why now reduce rotor excitation output voltage drops tu 220 v / 4 ohm output current is 55 a can why calculete like this.

Another example is car alternator have 900 w of pawer tu give that pawer with 13.7 v output current is 65 a and load resistance is 0.21077 this all calculation are based on ohm low.

Can why calculate like this of course every equipment must support rated current

also i understand principle of impedance can why calculate a show i above examples

if why can apply ohm's law tu alternator haw why can determinant output current

i am really confused about this because i am always thought that resistance determine the current same people say they alternator does not follow ohm law ok but haw then calculate current output and load itself
 
Engineering news on Phys.org
You are correct. You are applying ohm's law to the load resistor.
 
Have you studied anything about AC circuits ? Do you know the difference between resistance and inductive reactance ?

There's a concept called "Synchronous Impedance" that you should look up.

Impedance of an alternator is mostly inductive not resistive .

So your Ohm's Law must take into account the phase angles.

To determine synchronous impedance
1..Lock excitation at some value, probably rated for normal operating condition
then
2. With no load connected measure circuit voltage. That's Vinternal
3. Short circuit the output and measure how much current flows.

Divide result of EDIT result of 2 by result of 3, volts by amps..
You'll get the "Synchronous Impedance" for that alternator.
That many ohms of inductive reactance in series with Vinternal is the equivalent circuit of your alternator.
You can use that to predict alternator behavior if you know what is its excitation.

Remain aware that in automotive applications the voltage regulator adjusts excitation to keep output voltage constant.
So the alternator will appear to not follow Ohm's law .
That is probably what "same people" are telling you, is my guess.

What do you think ?

old jim
 
Last edited:
  • Like
Likes cnh1995
torbor said:
same people say they alternator does not follow ohm law ok but
Who are these people by the way? Your professor(s)? I remember one of my junior college professors saying 'transformer is an exception to Ohm's law.'
 
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top