- #1
adorrea
- 4
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Homework Statement
A block begins to slide down a ramp after being elevated to an angle of 53.75 degrees. What is the coefficient of static friction?
How do i find the coefficient of friction
- Thread starter adorrea
- Start date
AI Thread Summary
To find the coefficient of static friction for a block sliding down a ramp at an angle of 53.75 degrees, the relevant equations involve the normal force and net force on the incline. The normal force can be calculated using the formula normal force = m * g * cos(angle), while the net force is given by net force = m * g * sin(angle). The mass of the block is not necessary for the calculation, as it will cancel out in the equations. It is also assumed that the acceleration is zero at the point of static friction. Understanding these principles allows for the determination of the coefficient of static friction without needing the block's mass.
A block begins to slide down a ramp after being elevated to an angle of 53.75 degrees. What is the coefficient of static friction?
- #2
Villyer
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What formulas do you know regarding incline planes and friction?
- #3
adorrea
- 4
- 0
normal force=m*g*sin of angle and net force= m*g* cos of angle
- #4
adorrea
- 4
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will i have to find the mass of the block first
- #5
tiny-tim
Science Advisor
Homework Helper
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hi adorrea! 
no, call the mass "m" …
(and assume the acceleration is 0)
adorrea said:
no, call the mass "m" …
it'll cancel out in the end 
(and assume the acceleration is 0)
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question.
Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point?
Lets call the point which connects the string and rod as P.
Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
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