How do I find the derivative of a function with a given limit and function rule?

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Homework Statement



for all numbers x and y, let f be a function such that f(x+y)=f(x)+f(y)-2xy and such that the limit f(x)/h=7
h\rightarrow0
a. find f(0). Justify your answer.


b. Use the definition of the derivative to find the derivative of f(x)

c. Find f(x)

i already did section a and and got f(0) = 0, which my teacher said was correct. and i know that to get section c i would just take the integral of b. but i have absolutely no clue how to get b. would i just take the derivative of f(x+y)=f(x)+f(y)-2xy and set f(x+y) to 0? or do i take the derivative of
 
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The problem specifically says "use the definition of the derivative" which is, of course,
\lim_{h\rightarrow 0} \frac{f(x+ h)- f(x)}{h}
You are told that f(x+y)= f(x)+ f(y)- 2xy so f(x+h)= f(x)+ f(h)- 2xh.
\frac{f(x+h)- f(x)}{h}= \frac{f(h)- 2h}{h}= \frac{f(h)}{h}- 2<br /> What is the limit of that?
 
would the limit be as h approaches zero, since that would cause it to be undefined? my teacher really didn't explain how to do limits so I'm kinda lost
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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