- #1
raeshun
- 11
- 0
f(x)=x^2-3x-3x^-2+5x^-3
I need help finding the 1st derivative of this function using the power rule.If you can help can you explain how you got the answer.I tried like five times but the differentiation calculator says I am getting the wrong answer.heres how o attempted it.
f(x)'=(2)(x)^2-1 - (3)(x)^1-1 - (3)(-2)(x)^-2-1 + (-3)(5)(x)^-3-1
here i am applying the power rule to each variable, coefficient and exponent group they each have a different color to help you identify them with the original function.
f(x)'=2x-3+6x^-3 -15x^-4
and this is the answer i get
this is the answer i should get
f(x)'=(2x^5-3x^4+6x-15)/(x^4)
I need help finding the 1st derivative of this function using the power rule.If you can help can you explain how you got the answer.I tried like five times but the differentiation calculator says I am getting the wrong answer.heres how o attempted it.
f(x)'=(2)(x)^2-1 - (3)(x)^1-1 - (3)(-2)(x)^-2-1 + (-3)(5)(x)^-3-1
here i am applying the power rule to each variable, coefficient and exponent group they each have a different color to help you identify them with the original function.
f(x)'=2x-3+6x^-3 -15x^-4
and this is the answer i get
this is the answer i should get
f(x)'=(2x^5-3x^4+6x-15)/(x^4)
Last edited: