How do I go about solving this PDE?

  • Thread starter Thread starter coverband
  • Start date Start date
  • Tags Tags
    Pde
coverband
Messages
170
Reaction score
1

Homework Statement



\frac{\partial^2X}{\partial a^2} + (X^4-1)\frac{\partial X}{\partial a} = 0


Homework Equations



How do I go about solving this PDE ?

The Attempt at a Solution



Please help !
 
Physics news on Phys.org


Is X a vector? Then I would try rewriting it in polar coordinates. Otherwise this isn't a PDE and could be solved with the same method as is used with separation of variables.
 


How do you solve with s.o.v. ?
 


coverband said:
How do you solve with s.o.v. ?
Is it a pde or not? Ie, is X a vector or a single variable? As for how to solve it if it is an ODE, just integrate it with respect to a and then solve normally.
 


Ok. Let's call it an ODE: \frac{d^2y}{dx^2} + (y^4-1)\frac{dy}{dx} = 0

Now how solve please !
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top