How do I solve these physics problems involving variables and equations?

  • Thread starter Thread starter hoseA
  • Start date Start date
AI Thread Summary
The discussion focuses on solving physics problems involving variables and equations, particularly regarding electric potential and field calculations. The first problem is a multiple-choice question where the user is unsure about the variables involved and is researching the relevant equation. For the second problem, the user suggests that the potential is zero at specific points due to symmetry, while also identifying potential locations for zero potential. The third problem involves using the relationship between electric field and potential, with the user calculating a specific value based on the given equations. The conversation emphasizes the importance of understanding the concepts of electric potential and field in solving these types of physics problems.
hoseA
Messages
61
Reaction score
0
http://img423.imageshack.us/img423/4778/hwhelp1bs.jpg
The first one on the left is a Multiple Choice question. Just the mention of variables shuts down my brain. I'm still researching for the equation for the pbm.


The pbm in the right upper corner i think it's C and E. (by simply looking at it)

The pbm on the bottom right corner i used -E times delta r... I got -17.59.

Any help in the next 20-30 minutes will be much appreciated... as it'll double my homework score...
 
Last edited by a moderator:
Physics news on Phys.org
Potential is a scalar quantity. The distance of the points in all the 3 cases from the charges is same (they lie on the perpendicular bisector). So the net potential will be zero along these points (all are equal = 0).

For the right upper corner, consider the other point where the potential may be zero. There are three possibilites - right of +Q, between the charges and left of -2Q. One case is already given - right of +Q. Left of -2Q will be ruled out (Why?). So one case is left. Solve. (d/3)

For 3rd one use E = - (V/d)
or V = - E . d (E dot product d).
where d is the radius vector pointing from B to A.
 
For the second question answer is D+(2D/3) = 5D/3
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top