How do I work with a matrix like this?

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How do I work with a matrix like this??

Homework Statement



How do I go about solving a matrix like this:

[ 3e^4t -2e^3t ]
[ 4e^4t -5e^3t ]

Like how would I get the determinant and stuff? Do I avoid the exponent looking things, or get rid of them somehow??

Please help!

Homework Equations





The Attempt at a Solution

 
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Your matrix doesn't appear to be part of an equation, so there's nothing to solve. You can take the determinant of your matrix the same way you would any 2 x 2 matrix. You know how to multiply e^(at) by e^(bt), right?
 


Mark44 said:
Your matrix doesn't appear to be part of an equation, so there's nothing to solve. You can take the determinant of your matrix the same way you would any 2 x 2 matrix. You know how to multiply e^(at) by e^(bt), right?

Actually...no..

is it exponential multiplication?
 


Do you know how to multiply 2^3 by 2^4?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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