How Do Mass and Force Affect Acceleration in a Frictionless System?

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In a frictionless system involving a 2kg block hanging off a table and a 3kg block on the table, the total mass of the system is 5kg. The net force acting on the system is determined by the weight of the hanging block, which is 20N (2kg x 9.8m/s²). Using the equation F=ma, the acceleration of the blocks can be calculated as 4m/s² (20N/5kg). The discussion emphasizes focusing on the forces acting on the 3kg block to simplify the problem. Understanding these principles is crucial for solving related physics problems effectively.
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Homework Statement


A 2kg block hanging off the edge of a table pulls a 3kg block on a frictionless table. What is the mass of the system, the net force on the system, and th acceleration of the blocks.


Homework Equations


F=ma



The Attempt at a Solution


Not sure
20N and 30N so maybe net force 10N but not sure about the rest
 
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Hi there,

To simplify your solution, just look at what is acting on the 3kg block on the frictionless table.

Cheers
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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